Optimal. Leaf size=152 \[ -\frac{(e x)^{3/2} \left (\frac{a}{b x^2}+1\right )^{3/4} (2 b c-5 a d) F\left (\left .\frac{1}{2} \cot ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )\right |2\right )}{3 \sqrt{a} b^{3/2} \left (a+b x^2\right )^{3/4}}-\frac{e \sqrt{e x} \sqrt [4]{a+b x^2} (2 b c-5 a d)}{3 a b^2}+\frac{2 (e x)^{5/2} (b c-a d)}{3 a b e \left (a+b x^2\right )^{3/4}} \]
[Out]
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Rubi [A] time = 0.334732, antiderivative size = 152, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.269 \[ -\frac{(e x)^{3/2} \left (\frac{a}{b x^2}+1\right )^{3/4} (2 b c-5 a d) F\left (\left .\frac{1}{2} \cot ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )\right |2\right )}{3 \sqrt{a} b^{3/2} \left (a+b x^2\right )^{3/4}}-\frac{e \sqrt{e x} \sqrt [4]{a+b x^2} (2 b c-5 a d)}{3 a b^2}+\frac{2 (e x)^{5/2} (b c-a d)}{3 a b e \left (a+b x^2\right )^{3/4}} \]
Antiderivative was successfully verified.
[In] Int[((e*x)^(3/2)*(c + d*x^2))/(a + b*x^2)^(7/4),x]
[Out]
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Rubi in Sympy [A] time = 35.0309, size = 124, normalized size = 0.82 \[ \frac{d \left (e x\right )^{\frac{5}{2}}}{b e \left (a + b x^{2}\right )^{\frac{3}{4}}} + \frac{e \sqrt{e x} \left (5 a d - 2 b c\right )}{3 b^{2} \left (a + b x^{2}\right )^{\frac{3}{4}}} + \frac{2 \left (e x\right )^{\frac{3}{2}} \left (\frac{5 a d}{2} - b c\right ) \left (\frac{a}{b x^{2}} + 1\right )^{\frac{3}{4}} F\left (\frac{\operatorname{atan}{\left (\frac{\sqrt{a}}{\sqrt{b} x} \right )}}{2}\middle | 2\right )}{3 \sqrt{a} b^{\frac{3}{2}} \left (a + b x^{2}\right )^{\frac{3}{4}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((e*x)**(3/2)*(d*x**2+c)/(b*x**2+a)**(7/4),x)
[Out]
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Mathematica [C] time = 0.112707, size = 85, normalized size = 0.56 \[ \frac{e \sqrt{e x} \left (\left (\frac{b x^2}{a}+1\right )^{3/4} (2 b c-5 a d) \, _2F_1\left (\frac{1}{4},\frac{3}{4};\frac{5}{4};-\frac{b x^2}{a}\right )+5 a d-2 b c+3 b d x^2\right )}{3 b^2 \left (a+b x^2\right )^{3/4}} \]
Antiderivative was successfully verified.
[In] Integrate[((e*x)^(3/2)*(c + d*x^2))/(a + b*x^2)^(7/4),x]
[Out]
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Maple [F] time = 0.077, size = 0, normalized size = 0. \[ \int{(d{x}^{2}+c) \left ( ex \right ) ^{{\frac{3}{2}}} \left ( b{x}^{2}+a \right ) ^{-{\frac{7}{4}}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((e*x)^(3/2)*(d*x^2+c)/(b*x^2+a)^(7/4),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (d x^{2} + c\right )} \left (e x\right )^{\frac{3}{2}}}{{\left (b x^{2} + a\right )}^{\frac{7}{4}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x^2 + c)*(e*x)^(3/2)/(b*x^2 + a)^(7/4),x, algorithm="maxima")
[Out]
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{{\left (d e x^{3} + c e x\right )} \sqrt{e x}}{{\left (b x^{2} + a\right )}^{\frac{7}{4}}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x^2 + c)*(e*x)^(3/2)/(b*x^2 + a)^(7/4),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((e*x)**(3/2)*(d*x**2+c)/(b*x**2+a)**(7/4),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (d x^{2} + c\right )} \left (e x\right )^{\frac{3}{2}}}{{\left (b x^{2} + a\right )}^{\frac{7}{4}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x^2 + c)*(e*x)^(3/2)/(b*x^2 + a)^(7/4),x, algorithm="giac")
[Out]